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Our second table expands the first to show utility for various combinations of shirts and hamburgers. Thus, one shirt and three hamburgers give 32 utils of satisfaction (because 11 utils from shirts plus 21 utils from hamburgers equals 32 utils). The person gets the same level of satisfaction from five shirts and no hamburgers. The person whose wants are described in this table should find these two combinations of equal value, or, to anticipate a term, he will be indifferent between them.
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32 |
40 |
47 |
53 |
58 |
62 |
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31 |
39 |
46 |
52 |
57 |
61 |
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27 |
35 |
42 |
48 |
53 |
57 |
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20 |
28 |
35 |
41 |
46 |
50 |
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11 |
19 |
26 |
32 |
37 |
41 |
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0 |
8 |
15 |
21 |
26 |
30 |
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Number of Hamburgers |
The consumer wants to get as much utility as possible, but a budget constraint limits him. In the table above the budget constraint is drawn so that the person can have only five items. Looking at all combinations possible, that is, to the left of the budget constraint (the numbers in red), you should see that the combination three shirts and two hamburgers maximizes utility. This combination yields 42 utils and no other combination that is allowed by the budget constraint gives more.
This simple problem can be solved in another way, with the maximization principle. The advantage of the second solution is that it gives insight into a whole range of problems.